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1select year,count(*) as nr_contracts, count(distinct bytecode) as nr_distinct_bytecodes
2from @blt.ethereum_contracts.contracts
3group by all
4order by 2 desc1select year,count(*) as nr_contracts, count(distinct bytecode) as nr_distinct_bytecodes
2from @blt.ethereum_contracts.contracts
3group by all
4order by 2 descAnyone who has the link will be able to view this.